K(x)=2x-3x^2-4

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Solution for K(x)=2x-3x^2-4 equation: 



(K)=2K-3K^2-4

We move all terms to the left:

(K)-(2K-3K^2-4)=0

We get rid of parentheses

3K^2-2K+K+4=0

We add all the numbers together, and all the variables

3K^2-1K+4=0

a = 3; b = -1; c = +4;
Δ = b2-4ac
Δ = -12-4·3·4
Δ = -47
Delta is less than zero, so there is no solution for the equation

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